# raspberry

Rsactftool doesnt work for this one because n has multiple factors.

This is the script:

```python
primes = [2208664111,2214452749,2259012491,2265830453,2372942981,2393757139,2465499073,2508863309,2543358889,2589229021,2642723827,2758626487,2850808189,2947867051,2982067987,3130932919,3290718047,3510442297,3600488797,3644712913,3650456981,3726115171,3750978137,3789130951,3810149963,3979951739,4033877203,4128271747,4162800959,4205130337,4221911101,4268160257]

from Crypto.Util.number import inverse, long_to_bytes

n = 7735208939848985079680614633581782274371148157293352904905313315409418467322726702848189532721490121708517697848255948254656192793679424796954743649810878292688507385952920229483776389922650388739975072587660866986603080986980359219525111589659191172937047869008331982383695605801970189336227832715706317

e = 65537
ct = 5300731709583714451062905238531972160518525080858095184581839366680022995297863013911612079520115435945472004626222058696229239285358638047675780769773922795279074074633888720787195549544835291528116093909456225670152733191556650639553906195856979794273349598903501654956482056938935258794217285615471681

phi = 1
for p in primes:
  phi *= (p - 1)
d = inverse(e, phi)
pt = pow(ct, d, n)
decrypted = long_to_bytes(pt)
print(str(decrypted))
```

## flag:flag{there\_are\_a\_few\_extra\_berries\_in\_this\_one}
