Loading...
This one is just a Caesar cipher
binary > hex > octal > base64
Each character is divided by two, if it evenly divides | is used, else /.
|
/
I just had to multiply each ascii value by two, then add 1 accordingly.
inp = "9|2/9/:|4/7|8|4/2/1/2/9/" for i in range(0, len(inp), 2): char = ord(inp[i]) mod = inp[i+1] char = char*2 if mod == '/': char+=1 print(chr(char), end='')
Chuck it into https://incoherency.co.uk/image-steganography/#unhide
We then get an image revealed which contained the flag inside.
Again, chuck it into same link which gets you a load of qr codes in one image Open it in an online qr code reader Load of noise, but one pops out
volatility image, use hashdump
Use crackstation to crack them, then cyberchef to hash them
just use this online tool: Its a substitution cipher
volatility -f data --profile=Win7SP1x64 hashdump