Last updated 4 years ago
Starting from the top as 0, represent each colour as a base12 digit to get 86908187A349994397974192497B41977B44927B449698A5.
86908187A349994397974192497B41977B44927B449698A5
Then convert from base12 each 2 chars to get flag:
line = "86908187A349994397974192497B41977B44927B449698A5" n = 2 x = [line[i:i+n] for i in range(0, len(line), n)] o = "" for i in x: o += chr(int(i,12)) print(o)